WebApr 4, 2024 · We have that the pH of the solution derived to be. From the Question we are told that. Mass of CH3COONa=1.60g. Volume of CH3COONa v=40ml. 0.10 M acetic acid. Ka of CH3COOH is 1.75 × 10^-5. Generally the equation for the pH is mathematically given as. Where. Generally. And. Therefore returning to the initial pH equation. In conclusion WebAug 30, 2015 · Since Ka is small compared with the initial concentration of the acid, you can approximate (0.20− x) with 0.20. This will give you Ka = x2 0.2 ⇒ x = √0.2 ⋅ 1.78 ⋅ 10−4 = 5.97 ⋅ 10−3 The concentration of the hydronium ions will thus be x = [H3O+] = 5.97 ⋅ 10−3M This means that the solution's pH will be pH sol = − log([H3O+])
How do you calculate the pH of a buffer solution?
WebNov 28, 2024 · A buffer contains 0.10 mol of acetic acid and 0.13 mol of sodium acetate in 1.00L. a) What is the pH of the buffer? b) What is the pH of the buffer after the addition of 0.02 mol of KOH? c) What is the pH of the buffer after the addition of 0.02 mol of HNO3? WebApr 30, 2024 · Moles of NH+ 4 = 0.100 L × 0.1 mol 1 L = 0.010 mol So, we will have 200 mL of an aqueous solution containing 0.010 mol of ammonia, and the pH should be higher than 7. (ii) Calculate the pH of the solution [NH3] = 0.010 mol 0.200 L = 0.050 mol/L The chemical equation for the equilibrium is NH3 +H2O ⇌ NH+ 4 + OH- Let's re-write this as teman kbbi
pH of salt solutions (video) Khan Academy
WebDetermine the pH of each of the following solutions. 0.10 mol L−1 CH3COONa 0.11 mol L−1 NaCl This problem has been solved! You'll get a detailed solution from a subject matter … WebOct 18, 2024 · "pH" = 1.222 As you know, sodium hydroxide and hydrochloric acid neutralize each other in a 1:1 mole ratio as described by the balanced chemical equation "NaOH"_ ((aq)) + "HCl"_ ((aq)) -> "NaCl"_ ((aq)) + "H"_ 2"O"_ ((l)) This means that a complete neutralization, which would result in a neutral solution, i.e. a solution that has "pH" = 7 at … WebMay 31, 2024 · Calculate the pH of a buffer solution containing 0.1 mole of acetic acid and 0.15 mole of sodium acetate. Ionisation constant for acetic acid is 1.75 × 10-5. equilibrium class-11 1 Answer +1 vote answered May 31, 2024 by AashiK (75.9k points) selected May 31, 2024 by Vikash Kumar Best answer or, pH = - log 1.75 x 10-5 + log 1.5 = 4.9 teman kemenkeu